Question

Alex is making a blanket for her nephew. the blanket has a length of 5 ft and a width of 4 ft. she is going to sew ribbon edging around the perimeter of the blanket. the edging costs $3 per yard. How much will it cost for Alex to get the amount of ribbon edging that she needs? Hint: There are 3 feet in one yard.

Answer 1

Answer:

Step-by-step explanation:

What we have to do is calculate the area first, followed by calculation of that amount.

Now, there is a blanket. Dimensions :-

• 5 feet length
• 4 feet width

Let's find how much length she needs to sew first.

$\sf{Perimeter \ of \ a \ Rectangle = 2(Length + Breadth)}$

$\sf{Perimeter \ of \ a \ Rectangle = 2(5 + 4)}$

$\sf{Perimeter \ of \ a \ Rectangle = 18 \ feet}$

Now, the edging costs $3 per yard.

And, 1 yard = 3 feet.

We can convert feet to yard now.

3 feet = 1 yard

1 feet = $\dfrac{1}{3}$ yards.

18 feet = $\dfrac{18}{3}$

= $6$ yards.

Now, cost calculation :-

1 yard = $ 3

$6$ yards = $6 \times 3$

= $ 18 is the cost required for the edging of the ribbon.

Answer 2

Appropriate Question:

• Alex is making a blanket for her nephew. the blanket has a length of 5 ft and a width of 4 ft. she is going to sew ribbon edging around the perimeter of the blanket. the edging costs $3 per yard. How much will it cost for Alex to get the amount of ribbon edging that she needs?

To Find: Amount of ribbon edging that she needs.

__________________________

Given:

• Length of the blanket is 5ft
• Width of the blanket is 4ft
• 1 feet = 3 yard

As we know ,

$\dag\:\boxed{\frak { \pink{ Perimeter_{(Rectangle)} \:\: =\:\:  2( Length  + Breadth)\:\:}}}$

$\quad \dashrightarrow \sf Perimeter_{(Rectangle)} \:= 2(5+4)$

$\quad \dashrightarrow \sf Perimeter_{(Rectangle)} \:= 2 times 9$

$\quad \dashrightarrow \sf Perimeter_{(Rectangle)} \:= 18 \: Feet$

We know,

• The perimeter of the blanket is 18 feet.
• 3 feet = 1 yard
• 1 yard = $3

Now,

$\sf \: 3 \: feet = 1 \: yard \\ \sf 1 \: feet \: = \dfrac{1}{3} \\ \sf \: 18 \: feet \: = \: \dfrac{18}{3} \\ \sf \: 18 \: feet \: = \: \dfrac{ \cancel {18}}{ \cancel{3}} \\ \sf \: 18 \: feet \: = \: 6 \: yards$

Next,

$\sf \: 1 \: yard = \ \: 3 \\ \sf 6 \: yards \: = 6 \times 3 \\ \sf \: \: 6 \: yards \: = \ \: 18$