Alf has four times as many as Jim, and Jim has three times as many as Sid. Altogether they have 192. How many has each?
Answers
Answered by
0
Answer:
A+J+S = 192
A = 4J = 12S
J = 3S
12S + 3S + S = 192
16S = 192
S = 12
J = 36
A = 144
Alf has 144, Jim has 36, Sid has 12
Answered by
0
Step-by-step explanation:
Let
Sid be with x
Jim is with 3*x
=3x
Alf is with 4*3x
=12x
According to question
x + 3x +12x = 192
16x = 192
x = 12
so Sid = x= 12
Jim = 3x = 36
Alf = 12x = 144
Similar questions