Chemistry, asked by salimkhan275, 9 months ago

AlF₃ is soluble in HF only in presence of KF. It is due to the formation of
(1) К₃[AIF₃H₃]
(2) K₃ [AIF₆]
(3) AIH₃
(4) K[AIF₃H]

Answers

Answered by omasati2004
3

Answer:

AlF3 is insoluble in the anhydrous HF because the F ions are not available in intermolecular hydrogen bonded HF but it becomes soluble in the  presence of KF due to the formation of soluble complex,

K3[AlF6]

AlF3+3KF⟶K3[AlF6]

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