Question

Algeberic term of an arthametic 3n+1 what is common diference

Answer 1

Answer:

Let,

t(n) = 3n + 1

so,

if we let n =1

t(1)=3×1+1

t(1)=4

hence first term is 4.

now;

t = 2

t(2)=3×2+1

t(2)=7

second term is 7.

so,

commondiffernce=t(2)−t(1)

hence,

common difference = 7-4

common difference= 3.

FINAL ANSWER :

first term=4

common difference=3

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