Question

Algebra
1 The cost of 99 chairs and 101 tables is Rs 1996. The cost of 101 chairs and 99 tables is Rs 2004. Find the cost
of 1 chair and 2 tables
e) Rs28
d) Rs. 32
2. Cost of 2 apples, 3 oranges and 5 bananas is 15 rupees. Cost of 4 apples, 2 oranges and 10 bananas is 26 rupees.
Find cost of 1 orange
b) Rs. 2
c) Rs. 3
d) Rs. 4
3 2 apples 3 guavas and 5 bananas together cost Rs 10. 5 apples, 1 guava and 3 bananas together cost Rs 9.
What will be the cost of 19 apples, 9 guavas and 19 bananas together?
c) Rs. 53
d) None of These
A person starts with Rupees and y Paisa He spent R$ 3.50 and was left with Zy Rupees and 2x Paisa. What is
the value of (x + y)? 4 6
A clerk in a shipping dock weighs 5 crates kept in the dock in pairs. The pairwise weights are found to be 180
182, 183, 184, 185, 186, 187, 188, 190, 191 kgs respectively. Find the weight of the heaviest crate in kgs.
b) 97
c) 98
d) More information needed
a) 96​

Answer 1

Answer:

You can consider one item as X and another one as Y in each question.. then make 2 equations with the variables as asked in the question.. after that solve them, you will get the value of both X and y in each case... then multiply the value of X and y to the constant to how many times you need that thing...

for example in the 1st question..

let,

no. of chairs= x

no. of tables= y

ATQ,

99x + 101y = 1996

101x + 99y = 2004

then solve both the equations to get the value of X and y...

After getting the values you can find the cost of any no. of chairs and tables...