Algebra 2- Solutions by addition.
R-9S=2
3R-3S=-10
A. {(-4, -8/3)}
B. {(-4, -3/2)}
C. {(-4, -2/3)}
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Answer:
OPTION C
Step-by-step explanation:
eq 1
R=2+9S. 3RD EQUATION
PUT VALUE OF R IN EQ 2
3R-3S=-10
3(2+9S)-3S= - 10
6+27S - 3S = -10
24S= -16
S= -16÷24
S= -2/3
PUT THE VALUE OF S IN EQ 3
R=2+9S
R=2+9(- 2/3)
R=2-6
R= -4
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