Question

Algebra help please!!!

Solve for f.

d = 16ef²

f=±4√de
f=±√de/16
f=±√de/4e
f=±√4de/e

Solve for k.

J=k^2/4

k=±2J√
k=±4J√ ​
k=±2J√J
k=±4J

Answer 1

i am sorry i am not capable of solving it i am really sorry plzzzz forgive

Answer 2

Answer:

1)  $f=\pm\frac{1}{4}\sqrt{\frac{d}{e}}$  

2) $k=\pm 2\sqrt{J}$

Step-by-step explanation:

1)

Given : $d=16ef^2$

we have to solve for f.

Consider the given expression $d=16ef^2$

Divide both side by 16e, we get,

$\frac{d}{16e} =f^2$

Taking square root both side, we get,

$\sqrt{\frac{d}{16e}}=\sqrt{f^2}$

Simplify, we get,

$\sqrt{\frac{1}{16}}\sqrt{\frac{d}{e}}=f$

We know $\sqrt{16}=\pm 4$

Thus, $f=\pm\frac{1}{4}\sqrt{\frac{d}{e}}$  

2)

Given : $J=\farc{k^2}{4}$

we have to solve for k.

Consider the given expression $J=\farc{k^2}{4}$

Multiply both side by 4, we get,

$4J=k^2$

Taking square root both side, we get,

$\sqrt{4J}=\sqrt{k^2}$

$\sqrt{4J}=k$

We know $\sqrt{4}=\pm 2$ , we get,

$k=\pm 2\sqrt{J}$