Question

algebra question please don't have to be in your life​

Answer 1

Here,

we know that a/b= b/c

a= b²/c

b²=ac (1)

Now

LHS= b

b+c

multiplying both denominator and numerator with b-c

we have,

b × b-c

b+c b-c

b²-bc (2)

b²-c²

putting the value of b² in eq(2)

ac-bc

ac - c²

c(a-b)

c(a-c)

a-b

a-c

= R.H.S