Question

algebraic expression

Answer 1

Step-by-step explanation:

1; a+b+ab+b-c+bc+c+a+ac

=2a+2b+ab+ac+bc

=2(a+b)+a(b+c)+bc

4; 3-xy+yz-xz

= 3-xy-xz+yz

= 3-x(y+z)+yz

= (y+z)x-zy-3

now comparing with ax+by+c

a=(y+z), b=(-z), c=(-3)

5; using I'd

(a+b)(a-b)=a²-b²

(a+b+c)(a+b-c)=(a+b)²- (c)²

= a²+b²+2ab-c²