algebraic expression of 11,13,15 arthemetic sequence
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Answer:
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Step-by-step explanation:
11,13,15 a¹=11,a²=13,a³=15
d¹= a²-a¹=13-11=2 ,d²=a³-a²=15-13=2
therefore,
a⁴=a+3d=11+3x2=6
similarly you can find many
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