algebraic expression sn = 3n2+ 2n
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Answer:
an = Sn − Sn-1
Given,
Sn = 3n2 + 2n
∴ Sn-1 = 3(n − 1)2 + 2(n − 1)
(∴ an = Sn − Sn-1)
∴ an = 3n2 + 2n − {3(n − 1)2 + 2(n − 1)}
= 3n2 + 2n − {3(n2 − 2n + 1) + 2n − 2} =
3n2 + 2n − {3(n2 − 6n + 3 + 2n − 2} =
3n2 + 2n − {3(n2 − 4n + 1} =
6n − 1
Hence,
a2 = 6(2) − 1 = 11
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