Question

Algebraic form of an arithmetic sequence is 6n+2. a) What is the common difference? b) What is the sum of the first n terms of this sequence?​​

Answer 1

Answer:

Step-by-step explanation:

For any arithmetic sequence, first term has n=1. Hence first term is 6+2=8

6n+2

= 6n-6+8

=8+6(n-1).

Comparing with the standard expression of nth term of an arithmetic progression [a+d(n-1)] we have,

a=8, d=6