algebraic form of arithmetic sequence 1,6,11,16
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Answer:
Tn= 5n-4
Step-by-step explanation:
This is an arithmatic progression
The first term is 1=a, the common difference is 5= d.
Any term in this sequence can be written as Tn= a+ (n-1)d
where Tn is nth term, n is the number of term of the series, a is the first term, d is the common difference.
Tn =1+ (n-1)5
Tn= 1+ 5n-5
Tn= 5n-4
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