Math, asked by fajartk11, 5 hours ago

algebraic form of sequence 3,7,11,....​

Answers

Answered by dandekarsneha1002
0

Answer:

n/2 [4n + 2]

Step-by-step explanation:

hope it helps u.

Answered by Breh7
0

Answer:

Step-by-step explanation:

We think you wrote:

3,7,11,15

This deals with arithmetic sequences.

a2-a1=7-3=4

a3-a2=11-7=4

a4-a3=15-11=4

the difference between every two adjacent members of the series is constant and equal to 4

an=3+(n-1)4

a1=3   (this is the 1st member)

an=15  (this is the last/nth member)

d=4  (this is the difference between consecutive members)

n=4  (this is the number of members)

The sum of the members of a finite arithmetic progression is called an arithmetic series.

Using our example, consider the sum:

3+7+11+15

This sum can be found quickly by taking the number n of terms being added (here 4), multiplying by the sum of the first and last number in the progression (here 3 + 15 = 18), and dividing by 2:

n(a1+an)2

4(3+15) 2

The sum of the 4 members of this series is 36

This series corresponds to the following straight line y=4x+3

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