algebraic identify VII (3a-7b-c)2
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Using the identity,
(a+b+c)² = a²+b²+c²+2ab+2bc+2ac.
Now, put the value on the formula and execute...
⇒(3a-7b-c)²= (3a)²+(-7b)²+(-c)²+2.3a(-7b)+2.(-7b)(-c)+2.3b.(-c)
⇒(3a-7b-c)² = 9a²+49b²+c²-42ab+14bc-6ac.
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