Question

algebraic identities
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Answer 1

Answer:

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Step-by-step explanation:

Answer 2

Some Standard Algebraic Identities list are given below:

Some Standard Algebraic Identities list are given below:Identity I: (a + b)2 = a2 + 2ab + b2

Some Standard Algebraic Identities list are given below:Identity I: (a + b)2 = a2 + 2ab + b2Identity II: (a – b)2 = a2 – 2ab + b2

Some Standard Algebraic Identities list are given below:Identity I: (a + b)2 = a2 + 2ab + b2Identity II: (a – b)2 = a2 – 2ab + b2Identity III: a2 – b2= (a + b)(a – b)

Some Standard Algebraic Identities list are given below:Identity I: (a + b)2 = a2 + 2ab + b2Identity II: (a – b)2 = a2 – 2ab + b2Identity III: a2 – b2= (a + b)(a – b)Identity IV: (x + a)(x + b) = x2 + (a + b) x + ab

Some Standard Algebraic Identities list are given below:Identity I: (a + b)2 = a2 + 2ab + b2Identity II: (a – b)2 = a2 – 2ab + b2Identity III: a2 – b2= (a + b)(a – b)Identity IV: (x + a)(x + b) = x2 + (a + b) x + abIdentity V: (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca

Some Standard Algebraic Identities list are given below:Identity I: (a + b)2 = a2 + 2ab + b2Identity II: (a – b)2 = a2 – 2ab + b2Identity III: a2 – b2= (a + b)(a – b)Identity IV: (x + a)(x + b) = x2 + (a + b) x + abIdentity V: (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2caIdentity VI: (a + b)3 = a3 + b3 + 3ab (a + b)

Some Standard Algebraic Identities list are given below:Identity I: (a + b)2 = a2 + 2ab + b2Identity II: (a – b)2 = a2 – 2ab + b2Identity III: a2 – b2= (a + b)(a – b)Identity IV: (x + a)(x + b) = x2 + (a + b) x + abIdentity V: (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2caIdentity VI: (a + b)3 = a3 + b3 + 3ab (a + b)Identity VII: (a – b)3 = a3 – b3 – 3ab (a – b)

Some Standard Algebraic Identities list are given below:Identity I: (a + b)2 = a2 + 2ab + b2Identity II: (a – b)2 = a2 – 2ab + b2Identity III: a2 – b2= (a + b)(a – b)Identity IV: (x + a)(x + b) = x2 + (a + b) x + abIdentity V: (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2caIdentity VI: (a + b)3 = a3 + b3 + 3ab (a + b)Identity VII: (a – b)3 = a3 – b3 – 3ab (a – b)Identity VIII: a3 + b3 + c3 – 3abc = (a + b + c)(a2 + b2 + c2 – ab – bc – ca)