algebraic identities
Answers
Answer:
please writ in detail okkkkkkkkk
Step-by-step explanation:
Some Standard Algebraic Identities list are given below:
Some Standard Algebraic Identities list are given below:Identity I: (a + b)2 = a2 + 2ab + b2
Some Standard Algebraic Identities list are given below:Identity I: (a + b)2 = a2 + 2ab + b2Identity II: (a – b)2 = a2 – 2ab + b2
Some Standard Algebraic Identities list are given below:Identity I: (a + b)2 = a2 + 2ab + b2Identity II: (a – b)2 = a2 – 2ab + b2Identity III: a2 – b2= (a + b)(a – b)
Some Standard Algebraic Identities list are given below:Identity I: (a + b)2 = a2 + 2ab + b2Identity II: (a – b)2 = a2 – 2ab + b2Identity III: a2 – b2= (a + b)(a – b)Identity IV: (x + a)(x + b) = x2 + (a + b) x + ab
Some Standard Algebraic Identities list are given below:Identity I: (a + b)2 = a2 + 2ab + b2Identity II: (a – b)2 = a2 – 2ab + b2Identity III: a2 – b2= (a + b)(a – b)Identity IV: (x + a)(x + b) = x2 + (a + b) x + abIdentity V: (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca
Some Standard Algebraic Identities list are given below:Identity I: (a + b)2 = a2 + 2ab + b2Identity II: (a – b)2 = a2 – 2ab + b2Identity III: a2 – b2= (a + b)(a – b)Identity IV: (x + a)(x + b) = x2 + (a + b) x + abIdentity V: (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2caIdentity VI: (a + b)3 = a3 + b3 + 3ab (a + b)
Some Standard Algebraic Identities list are given below:Identity I: (a + b)2 = a2 + 2ab + b2Identity II: (a – b)2 = a2 – 2ab + b2Identity III: a2 – b2= (a + b)(a – b)Identity IV: (x + a)(x + b) = x2 + (a + b) x + abIdentity V: (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2caIdentity VI: (a + b)3 = a3 + b3 + 3ab (a + b)Identity VII: (a – b)3 = a3 – b3 – 3ab (a – b)
Some Standard Algebraic Identities list are given below:Identity I: (a + b)2 = a2 + 2ab + b2Identity II: (a – b)2 = a2 – 2ab + b2Identity III: a2 – b2= (a + b)(a – b)Identity IV: (x + a)(x + b) = x2 + (a + b) x + abIdentity V: (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2caIdentity VI: (a + b)3 = a3 + b3 + 3ab (a + b)Identity VII: (a – b)3 = a3 – b3 – 3ab (a – b)Identity VIII: a3 + b3 + c3 – 3abc = (a + b + c)(a2 + b2 + c2 – ab – bc – ca)