Question

Algebraic Identities Case I(a3 + b3) and Case II (a3 – b3).

Answer 1

Step-by-step explanation:

CASE-I:

(a+b)³=(a+b)(a+b)(a+b)

=(a+b)²(a+b)

=(a²+2ab+b²)(a+b)

=a(a²+2ab+b²)+b(a²+2ab+b²)

=a³+ab²+2a²b+ba²+b³+2ab²

=a³+b³+3ab²+3a²b

=a³+b³+3ab(b+a)

(a+b)³=a³+b³+3ab(a+b)

a³+b³=(a+b)³-3ab(a+b)