Question

algebraic identities examples​

Answer 1

Answer:

Some Standard Algebraic Identities list are given below:

Some Standard Algebraic Identities list are given below:Identity I: (a + b)2 = a2 + 2ab + b2

Some Standard Algebraic Identities list are given below:Identity I: (a + b)2 = a2 + 2ab + b2Identity II: (a – b)2 = a2 – 2ab + b2

Some Standard Algebraic Identities list are given below:Identity I: (a + b)2 = a2 + 2ab + b2Identity II: (a – b)2 = a2 – 2ab + b2Identity III: a2 – b2= (a + b)(a – b)

Some Standard Algebraic Identities list are given below:Identity I: (a + b)2 = a2 + 2ab + b2Identity II: (a – b)2 = a2 – 2ab + b2Identity III: a2 – b2= (a + b)(a – b)Identity IV: (x + a)(x + b) = x2 + (a + b) x + ab

Some Standard Algebraic Identities list are given below:Identity I: (a + b)2 = a2 + 2ab + b2Identity II: (a – b)2 = a2 – 2ab + b2Identity III: a2 – b2= (a + b)(a – b)Identity IV: (x + a)(x + b) = x2 + (a + b) x + abIdentity V: (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca

Some Standard Algebraic Identities list are given below:Identity I: (a + b)2 = a2 + 2ab + b2Identity II: (a – b)2 = a2 – 2ab + b2Identity III: a2 – b2= (a + b)(a – b)Identity IV: (x + a)(x + b) = x2 + (a + b) x + abIdentity V: (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2caIdentity VI: (a + b)3 = a3 + b3 + 3ab (a + b)

Some Standard Algebraic Identities list are given below:Identity I: (a + b)2 = a2 + 2ab + b2Identity II: (a – b)2 = a2 – 2ab + b2Identity III: a2 – b2= (a + b)(a – b)Identity IV: (x + a)(x + b) = x2 + (a + b) x + abIdentity V: (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2caIdentity VI: (a + b)3 = a3 + b3 + 3ab (a + b)Identity VII: (a – b)3 = a3 – b3 – 3ab (a – b)

Some Standard Algebraic Identities list are given below:Identity I: (a + b)2 = a2 + 2ab + b2Identity II: (a – b)2 = a2 – 2ab + b2Identity III: a2 – b2= (a + b)(a – b)Identity IV: (x + a)(x + b) = x2 + (a + b) x + abIdentity V: (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2caIdentity VI: (a + b)3 = a3 + b3 + 3ab (a + b)Identity VII: (a – b)3 = a3 – b3 – 3ab (a – b)Identity VIII: a3 + b3 + c3 – 3abc = (a + b + c)(a2 + b2 + c2 – ab – bc – ca

Answer 2

$\begin{gathered}\boxed{\begin{array}{l}\boxed{\bigstar\:\:\textbf{\textsf{Algebric\:Identity}}\:\bigstar}\\\\\frak{1.}\bf\:(A+B)^{2} = A^{2} + 2AB + B^{2}\\\\\frak{2.}\sf\: (A-B)^{2} = A^{2} - 2AB + B^{2}\\\\\frak{3.}\bf\: A^{2} - B^{2} = (A+B)(A-B)\\\\\frak{4.}\sf\: (A+B)^{2} = (A-B)^{2} + 4AB\\\\\frak{5.}\bf\: (A-B)^{2} = (A+B)^{2} - 4AB\\\\\frak{6.}\sf\: (A+B)^{3} = A^{3} + 3AB(A+B) + B^{3}\\\\\frak{7.}\bf\:(A-B)^{3} = A^{3} - 3AB(A-B) + B^{3}\\\\\frak{8.}\sf\: A^{3} + B^{3} = (A+B)(A^{2} - AB + B^{2})\\\\\end{array}}\end{gathered}$