Question

algebraic identities (x+5)^3​

Answer 1

Given,

☞ (x+5)³

$\boxed{\tt{(a+b)³ = a³+3a²b+3ab²+b³}}$

$→\;{\bf{ x³+3x²5+5³+3x5²}}$

$→\;{\bf{x³+15x²+125+3x25}}$

$◕➜\;{\red{\sf{x²+15x²+75x+125}}}$

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