Question

algebric expression division 1+y^3 by 1+y
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Answer 1

Answer:

Rule:

Quotient of two monomials = (quotient of their numerical coefficients) x (quotient of their variables)

Step-by-step explanation:

Answer 2

$Given \: \frac{1 + y^{3}}{(1+y)}$

$= \frac{1^{3} + y^{3}}{(1+y)}$

$= \frac{(1+y)(1^{2} - 1 \times y + y^{2})}{(1+y)}$

/* By algebraic identity */

$\boxed{\pink{ a^{3}+b^{3} = (a+b)(a^{2}-ab+b^{3}) }}$

$= 1-y+y^{2}$

Therefore.,

$\red{ \frac{1 + y^{3}}{(1+y)} }$

$\green { = 1-y+y^{2}}$

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