algebric form of the sequence 1,5,9,13,17
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Step-by-step explanation:
1, 5, 9, 13, 17, 21, 25, 29, . . ., 4n+1, . . . In general, the terms of an arithmetic sequence with the first term a0 and common difference d, have the form an = dn+a0 (n=0,1,2,...).
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Answer:
algebric form of the sequence 1,5,9,13,17
an=4n-3
where n is a natural number
Step-by-step explanation:
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