algebric solution of a^8+b^8
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By using the formula,
x²-y²=(x+y)(x-y)
= (b⁴ + a⁴)(b⁴ - a⁴)
= (b⁴ + a⁴)( (b²)² - (a²)²)
= (b⁴ + a⁴)(b² + a²)(b² - a²)
= (b⁴ + a⁴)(b² + a²)(b + a)(b - a)
-a⁸ + b⁸ = (b⁴ + a⁴)(b² + a²)(b + a)(b - a)
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