Algibric form of an arithmetic sequence is 4n+5 find common difference first term and remainder
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Step-by-step explanation:
given that 4n+5 is the algebraic form
therefore common difference d =4
first no =5
proof
let us consider an A.P of the first digit 'n' and common difference 'd'
the second term of the sequence will be n+ d
the third term of the sequence will be n+d+d i.e, n+2d .........this will continue
hope U understand ...........
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