Question

ALI.
In the ultraviolet region of the atomic spectrum
of hydrogen, a line is obtained at 1026 Aº.
Calculate the energy of photon of this
wavelength (h = 6.626 x 10-34 J sec).​

Answer 1

Explanation:

1. if thita and bitta are the roots of the equation 3x^2+x-10=0 then the value of 1/bitta + 1/thitta is ........a)10 , b) -1/10, c) 1/10, d) 1/3

Answer 2

Answer:

$19 \times 10^{-19}$ J

Explanation:

Energy = frequency x h

frequency = $\frac{c}{\lambda}$ where $\lambda$ = wavelegnth.

c = speed of light in space ( $3 \times 10^{8}$ m$s^{-1}$)

$1 A^{o} = 10^{-10} m$

energy = $\frac{hc}{\lambda}$ =  $19 \times 10^{-19}$J or $11.875$ eV

Thanks!