Question

Alia is thrice as old as Reema. Haya is 7 years younger than Alia. If the sum of their ages is 28, how old are the three girls?

Answer 1

Answer:

age of reema= x

age of alia= 3x

age of haya= 3x-7

x + 3x + 3x-7=28

7x-7=28

7x=28-7

7x=21

x=21/7

x=3

reema=x=3 years

alia=3x=9 years

haya=3x-7=9-7=2 years

Step-by-step explanation:

Answer 2

The age of Reema is 5 years.

The age of Alia is 15 years.

The age of Haya is 8 year.

Step-by-step explanation:

Given : Alia is thrice as old as Reema. Haya is 7 years younger than Alia. If the sum of their ages is 28.

To find : How old are the three girls?

Solution :

Let the age of Reema be 'x'.

The age of Alia is '3x'

The age of Haya is '3x-7'

The sum of their ages is 28.

i.e. $x + 3x + 3x-7=28$

$7x-7=28$

$7(x-1)=28$

$x-1=\frac{28}{7}$

$x-1=4$

$x=5$

The age of Reema is 5 years.

The age of Alia is 3(5)=15 years

The age of Haya is 3(5)-7=15-7=8 years

#Learn more

9 years Hence a girl will be three times as old as she was 9 years ago how old she is now ?

https://brainly.in/question/5106503