Alica has 5 real numbers a < b < c < d < e. She takes the sum of each pair of numbers and writes down the ten sums. The three smallest sums are 32, 36, 37 while the two largest sums are 51 and 48. Find the value of 2e.
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32 < 36 < 37 < 48 < 51 is answer for it question
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Given : Alica has 5 real numbers a < b < c < d < e.
She takes the sum of each pair of numbers and writes down the ten sums. The three smallest sums are 32, 36, 37
while the two largest sums are 51 and 48.
To find : the value of 2e.
Solution:
a + b = 32
a + c = 36
b + c = 37
(a + b) + ( a + c) - ( b + c) = 32 + 36 - 37
=> 2a = 31
a = 15.5
b = 16.5
c = 21.5
c + e = 48
=> e = 26.5
=> 2e = 53
the value of 2e = 53
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Alica has 5 real numbers
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