All 3 digit natrual numbers is a defined set ?
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Step-by-step explanation:
If all digits are odd, each digit must be taken from set {1,3,5,7,9}, which has cardinality 5. Assuming that repetitions are allowed, there are then 5^3 = 125 natural numbers with 3 digits in which all digits are odd.
If all digits are even, the first digit must be taken from {2,4,6,8}, whereas the second and third digits must be taken from {0,2,4,6,8}. Therefore, the number of 3-digit natural numbers in which all digits are even is 4.(5^2) = 4x25 = 100.
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