Question

ALL
algebraic
identities in one by one number wise​

Answer 1

Answer:

a2 + b2 = (a – b)2 + 2ab.

(a – b)2 = a2 – 2ab + b2.

(a + b + c)2 = a2 + b2 + c2 + 2ab + 2ac + 2bc.

(a – b – c)2 = a2 + b2 + c2 – 2ab – 2ac + 2bc. (a + b)3 = a3 + 3a2b + 3ab2 + b3 ;

(a + b)3 = a3 + b3 + 3ab(a + b)