Question

All black cards are removed from a pack of 52 playing cards. the remaining cards are well shuffled and then a card is drawn at random .find the probability of getting (i) face card (ii) queen. step by step explanation plz.​

Answer 1

Step-by-step explanation:

6

1- p (E) = ----

26

2

2 - p ( E) = ----

26

Answer 2

GIVEN:

• All black cards are removed from a pack of 52 cards.
• A card is drawn at random.

TO FIND:

• Probability of getting a face card and queen

FORMULA USED:

Probability = $\rm\green{\dfrac{Number\: of \:possible \:outcomes}{Total\: number \:of\: outcomes}}$

SOLUTION:

Since all black cards are removed from a pack so there are total 26 cards left in the pack

Total cards = Total number of outcomes = 26

i) $\rm\blue{Probability \:of\: getting \:a\: face card}$

There are total 12 face cards in a deck ( 6 red and 6 black) but 6 black cards are removed. So, there are only 6 red face cards left.

Number of possible outcomes(face card) = 6

Probability ( of face card ) = $\rm{\dfrac{6}{26}={\boxed{\red{\dfrac{3}{13}}}}}$

ii) $\rm\blue{Probability\: of\: getting \:a \:queen}$

There are total 4 queens in a deck ( 2 red and 2 black) but 2 black queens are removed. So, there are only 2 queens left.

Number of possible outcomes(queens) = 2

Probability ( of a queen ) = $\rm{\dfrac{2}{26}={\boxed{\red{\dfrac{1}{13}}}}}$

ANSWER:

$\rm\longmapsto\green{Probability\:of\:getting\:a\:face\:card\:is\:\dfrac{3}{13}}$

$\rm\longmapsto\green{Probability\:of\:getting\:a\:queen\:is\:\dfrac{1}{13}}$

Note:- Swipe from right towards left to see the complete answer :)

@BrainlicaLDoll