Question

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DESENE
ZU
19. A metallic ring of mass 1 kg has moment
of inertia 1 kg m² when rotating about
one of its diameters. It is molten and
remoulded into a thin uniform disc of the
same radius. How much will its moment
of inertia be, when rotated about its own
axis.
[Ans: 1 kg mº]​

Answer 1

Answer:

Ring I = MR²/2

=> 1 = 1*R²/2

=> R =√2

DISC I' = MR²/2

=> I'= 1 * (√2)²/2

=> I' = 2/2

=> I'= 1 kg m²

Answer 2

Answer:

ring 1=mr2 /2

1'=r2 /2

r=2

disc =mr2 /2

1'=1 (2)2 /2

1'=2/2

1'=1kg m2

this answer is correct answer

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