Question

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English
The product of the ages of Rand S is 540.If twice the age of R is more than S's age by 6 years, then find sum of R's age and S's age?​

Answer 1

Answer:

51 years

Step-by-step explanation:

Let R's age be X and S's age be (540/X)

So,

2X - (540/X) = 6

or, 2X^2 -540 = 6X

or, 2X^2-6X-540 = 0

or, X^2-3X-270 = 0

or, X^2-18X+15X-270 = 0

or, X(X-18)+15(X-18) = 0

or, (X-18) (X+15) = 0

So, X = 18

[As age cannot be negative so X ≠ -15]

So, R's age = 15 years

And S's age = (540/15) years = 36 years

Hence, the sum of R and S's age = (15+36)

= 51 years