Question

All face cards (kings, queens and jacks) are
removed from a deck of 52 playing cards and
then well shuffled. One card is selected from
the remaining cards. The probability of this
card to be a diamond is​

Answer 1

$\huge\red{\underline{{\bf❥A}}}\huge\orange{\underline{{\bf n}}}\huge\green{\underline{{\bf s}}}\huge\blue{\underline{{\bf w}}}\huge\purple{\underline{{\bf e}}}\huge\pink{\underline{{\bf r}}}$

Probability of a diamond card = 1/4

Step-by-step explanation:

.

Please see the detailed answer in picture.

.

$\huge\bold{\mathtt{\purple{ H{\pink{ o{\green{ p{\blue{ e{\red{ .{\orange{ i{\purple{ t{\pink{ s{\green{ .{\blue{ H{\red{ e{\purple{ l{\pink{ p{\green{ .{\blue{ U!}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}$

Answer 2

$no \: of \: face \: cards \: in \: a \: deck \: = \: 12 \\ no \: of \: tye \: total \: remaining \: cards \: = 52 - 12 = 40 \\ the \: probability \: ofthe \: drawn \: card \: to \: be \: a \: diamond \: is \: = \frac{9}{40}$

hope this helps you ! mark as brainliest of you are satisfied please !