Question

ALL FARMULA OF ● Surface area and Volume CLASS 10 CBSE...




help me thank you.........​

Answer 1

HERE  IS YOUR ALL FORMULAS OF MENSURATION

CUBOID:-

(1) VOLUME OF CUBOID = L×B×H

(2) CSA OF CUBOID= 2(lb+bh+lh)

(3) TSA OF CUBOID= 2(L+B)×H

CUBE:-

(1) VOLUME OF CUBE = A³

(2) CSA OF CUBE= 4A²

(3) TSA OF CUBE = 6A²

CYLINDER:-

(1) VOLUME OF CYLINDER= πR²H

(2) CSA OF CYLINDER= 2πRH

(3) TSA OF CYLINDER= 2πR(H+R)

CONE:-

(1) VOLUME OF CONE = 1/3πR2H

(2) CSA OF CONE = πRL

(3) TSA OF CONE = πRL +πR² = πR(L+R)

SPHERE:-

(1) VOLUME OF SPHERE = 4/3πR³

(2) TSA OF SPHERE = 4πr²

HEMISPHERE :-

(1) VOLUME OF HEMISPHERE = 2/3πR³

(2) CSA OF HEMISPHERE =  2 π r2

(3) TSA OF HEMISPHERE = 3 πr2

FRUSTUM OF CONE:-

(1) VOLUME = 1/3πh(R²+r²+ Rr)

(2) CSA = πL(R+r)

HOPE IT WILL HELP YOU..

ALL THE BEST FOR THE EXAM

Answer 2

✌✌hey here is ur ans ..✌✌

All the formulas of Class 10th cbse Surface area nd volumes ....

☆ CUBE

▪ T.S.A - 6(a)^2

▪ C.S.A - 4 (a)^2

▪ Volume - (a)^3

☆ CUBOID

▪ T.S.A - 2 ( lb + bh + hl )

▪ C.S.A - 2h ( l + b )

▪ Volume - lbh

☆ CYLINDER

▪ $tsa = 2\pi \: r(r + h)$

▪ $csa =2 \pi \: r \: h$

▪ $volume \: = \pi \: {r}^{2} h$

☆ CONE

▪ $tsa = \pi \: r \: (r + l)$

▪ $csa = \pi \: r \: l$

▪ $volume = 1 \div 3\pi \: {r}^{2} h$

☆ SPHERE

▪ $surface \: \: area \: = 4\pi \: { r}^{2}$

▪ $volume \: = 4 \div 3\pi \: {r}^{3}$

☆ HEMISPHERE

▪ $tsa = 3\pi \: {r}^{2}$

▪ $csa \: = 2\pi \: {r}^{2}$

▪ $volume \: = 2 \div 3\pi \: {r}^{3}$

☆ FRUSTUM OF A CONE

▪ T.S.A - pi[R^2 + r^2 + l(R + r)]
▪ C.S.A - pi l ( R + r )
▪ Volume - 1/3 pi h [ R^2+ r^2 + Rr ]

hope it will help uh ..
nd plz mark as brainliest ..☺☺