all formula of comparing quantities ....
Answers
For Example:-
New or final price of an apple =Rs 25
Old or initial price of an apple = Rs 20
Thus, %increase = 100 = 25%
Decrease percent:-
% decrease = 100
For Example:-
New or final price of an apple =Rs. 20
Old or initial price of an apple = Rs. 25
Thus % decrease = 100 = 20%
Important Formulas:-
C.P. = S.P. – Profit
C.P. = S.P. + Loss
S.P. = C.P. + Profit
S.P. = C.P. – Loss
Profit (P) = S.P. -C.P.
Loss (L) = C.P. – S.P.
Profit % = 100
Loss % = 100
Discount (D) = Marked Price (M.P.) – Selling price
Discount % = 100
Net Price = S.P = Marked Price (M.P) – Discount (D)
Where, C.P. is Cost Price and S.P is Selling Price.
Sales Tax:-
Bill Amount = Cost of item + Sales tax
Formulas:-
Value added tax = Tax charged – Tax paid.
Value added tax = Tax % (S.P. – C.P.)
Simple Interest:-
Simple Interest =
For Example:-
A sum of Rs. 10,000 is borrowed at a rate of interest 15% per annum for 2 years. Find the simple interest on this sum and the amount to be paid at the end of 2 years.
Solution:-
On Rs. 100, interest charged for 1 year is 15%.
So, on Rs. 10,000, interest charged = 10000
= 1500 Interest for 2 years
= 1500 × 2
= 3000
Amount to be paid at the end of 2 years
= Principal + Interest
= 10000 + 3000
= 13000
Compound Interest:-
Compound interest (C.I.) = Amount (A) – Principal (P)
A = P (1 + n
C.I = P [(1 + n -1]
Where, the principal be P, time be n years and rate be R
For Example:-
Find CI on ` 12600 for 2 years at 10% per annum compounded annually.
Solution:-
, where Principal (P) = Rs.12600, Rate(R) = 10 and Number of years (n) = 2
So,
Compound interest (compounded half-yearly):-
A = P (1 + 2n
For Example:-
What amount is to be repaid on a loan of Rs. 12000 for years at 10% per annum compounded half yearly.
Solution:-
Given: n = , P = 12000, and r = 10%
A = P (1 + 2n
Calculation of growth:-
Production after n years = Initial (original) Production × (1 + n
R% = rate of growth in production.
Depreciation:-
If the cost of a machine depreciates by R% every year, then its value after n years is
Value after n years = Present value × (1 + n
Calculation of Population:-
Population after n years = Present Population × (1 + n
R% = rate of increase in population
Answer:
Increase percent:-
% increase = 100
For Example:-
New or final price of an apple =Rs 25
Old or initial price of an apple = Rs 20
Thus, %increase = 100 = 25%
Decrease percent:-
% decrease = 100
For Example:-
New or final price of an apple =Rs. 20
Old or initial price of an apple = Rs. 25
Thus % decrease = 100 = 20%
Important Formulas:-
C.P. = S.P. – Profit
C.P. = S.P. + Loss
S.P. = C.P. + Profit
S.P. = C.P. – Loss
Profit (P) = S.P. -C.P.
Loss (L) = C.P. – S.P.
Profit % = 100
Loss % = 100
Discount (D) = Marked Price (M.P.) – Selling price
Discount % = 100
Net Price = S.P = Marked Price (M.P) – Discount (D)
Where, C.P. is Cost Price and S.P is Selling Price.
Sales Tax:-
Bill Amount = Cost of item + Sales tax
Formulas:-
Value added tax = Tax charged – Tax paid.
Value added tax = Tax % (S.P. – C.P.)
Simple Interest:-
Simple Interest =
For Example:-
A sum of Rs. 10,000 is borrowed at a rate of interest 15% per annum for 2 years. Find the simple interest on this sum and the amount to be paid at the end of 2 years.
Solution:-
On Rs. 100, interest charged for 1 year is 15%.
So, on Rs. 10,000, interest charged = 10000
= 1500 Interest for 2 years
= 1500 × 2
= 3000
Amount to be paid at the end of 2 years
= Principal + Interest
= 10000 + 3000
= 13000
Compound Interest:-
Compound interest (C.I.) = Amount (A) – Principal (P)
A = P (1 + n
C.I = P [(1 + n -1]
Where, the principal be P, time be n years and rate be R
For Example:-
Find CI on ` 12600 for 2 years at 10% per annum compounded annually.
Solution:-
, where Principal (P) = Rs.12600, Rate(R) = 10 and Number of years (n) = 2
So,
Compound interest (compounded half-yearly):-
A = P (1 + 2n
For Example:-
What amount is to be repaid on a loan of Rs. 12000 for years at 10% per annum compounded half yearly.
Solution:-
Given: n = , P = 12000, and r = 10%
A = P (1 + 2n
Calculation of growth:-
Production after n years = Initial (original) Production × (1 + n
R% = rate of growth in production.
Depreciation:-
If the cost of a machine depreciates by R% every year, then its value after n years is
Value after n years = Present value × (1 + n
Calculation of Population:-
Population after n years = Present Population × (1 + n
R% = rate of increase in population.
Step-by-step explanation:
hope the answer help you