Question

all formulas for trigonometry and differentiation and integrationist

Answer 1

Heyy frnd here is ur answer

cosec theta=1/sin theta
sec theta=1/cos theta
cot theta=1/tan theta

sin theta= p/h
cos theta=b/h
tan theta= p/b
cosec theta= h/p
sec theta=h/b
cot theta= b/h

tan theta = sin theta/cos theta
cot theta =cos theta /sin theta
tan theta × cot theta = 1

$sin ^{2} theta + \cos ^{2} theta = 1$
$1 + \tan^{2} theta \: = \sec ^{2} theta$
$1 + \cot ^{2} theta = \csc ^{2} \:theta$

sin(90 degree - theta) = cos theta

cos ( 90 degree - theta) = sin theta
tan (90 degree - theta)= cot theta
cot (90 degree - theta) =tan theta
sec (90degree - theta) = cosec theta
cosec(90 degree -theta) = sec theta