Math, asked by Ajay2929, 1 year ago

All king,Jack and Diamonds have been removed from a pack of cards and remaining cards are well shuffled.A card is drawn at random.Find the probability.(i)A Red Queen (ii)A face card (iii)A Diamond (iv)A Black (v)A Black Jack.

Answers

Answered by Vaishnav33
41
hope it's helpfull............
Attachments:

Vaishnav33: if you find it helpful... mark it as brainlist....
Ajay2929: ok
Vaishnav33: thanks........
Answered by amitnrw
19

Probability of Red Queen = 1/33

Step-by-step explanation:

All king,Jack and Diamonds have been removed from a pack of cards

Total card = 52

king = 4

Jack = 4

Diamond = 13

king & jack of Diamond = 2

Remaining Card = 52 - 4 - 4 - 13 + 2 = 33

i)A Red Queen  - Only Heart Queen  as Diamond queen removed

= 1/33

(ii)A face card  = 3 Queen only   as ( king , Jack removed & Diamond Queen removed)

= 3/33

= 1/11

(iii)A Diamond  = 0  ( all Diamonds have been removed)

= 0

(iv) A Black  = 26 - 2 - 2 = 22  ( 2 king & 2 Jack of Black removed)

= 22/33

= 2/3

(v)A Black Jack. = 0  ( as all Jacks removed)

= 0

Learn more:

Two cards are drawn at random from a deck of 52 cards. If ...

https://brainly.in/question/11729005

A card is drawn at random from a pack of well shuffled 52 playing ...

https://brainly.in/question/11759479

Two cards are drown from a pack of cards in a succession with ...

https://brainly.in/question/9029657

Similar questions