All letters of the word eamcot are arranged in different possible ways.find the number of arrangements in which no 2 vowels are adjacent to each other
Answers
Answered by
12
consonant= 3
vowels=3 E, A and O.
Since no two vowels have to be together,
The sequence will some what like; taking ‘X’ as a vowel.
X M X C X T X,
so the permutation will be like 4P3 =144
vowels=3 E, A and O.
Since no two vowels have to be together,
The sequence will some what like; taking ‘X’ as a vowel.
X M X C X T X,
so the permutation will be like 4P3 =144
Similar questions