all natural numbers between 101 and 304 which are divisible by 3 or 5
i need it step by step
Answers
Answered by
2
Answer:
19035
Step-by-step explanation:
given- numbers between 101 and 304 which are divisible by 3 or 5 .
FIND- all natural numbers between 101 and 304 .
solution- all natural numbers between 101 and 304 which are divisible by 3 are 102, 105, ......303.
first term a= 102
common difference d= 3
let there be n term in this AP
n^th term = 303
a+(n-1) d=303
102+( n-1) = 303
n-1= 67
n= 68.....(1)
numbers between 101 and 304 which are divisible by 5 are 105 , 110 ....300.
a=105 d= 5
n^th term = 300
a+(n-1) d=300
105+(n-1) =300
n-1= 13
n=14
from eq 1 2 and 3
their sum 568+540-514
34(102×2+67×3) +20 ( 105×2+39×5)-7(105×2+13×15)
=34(204+201) + 20(210 +195)
-7 ( 210+195)
13770+ 8100-2835)
= 19035
FINAL ANSWER- 19035
#SPJ3
Similar questions