Math, asked by Jennifer31, 10 months ago

all natural numbers between 101 and 304 which are divisible by 3 or 5
i need it step by step​

Answers

Answered by pannurekha166
2

Answer:

19035

Step-by-step explanation:

given- numbers between 101 and 304 which are divisible by 3 or 5 .

FIND- all natural numbers between 101 and 304 .

solution- all natural numbers between 101 and 304 which are divisible by 3 are 102, 105, ......303.

first term a= 102

common difference d= 3

let there be n term in this AP

n^th term = 303

a+(n-1) d=303

102+( n-1) = 303

n-1= 67

n= 68.....(1)

numbers between 101 and 304 which are divisible by 5 are 105 , 110 ....300.

a=105 d= 5

n^th term = 300

a+(n-1) d=300

105+(n-1) =300

n-1= 13

n=14

from eq 1 2 and 3

their sum 568+540-514

34(102×2+67×3) +20 ( 105×2+39×5)-7(105×2+13×15)

=34(204+201) + 20(210 +195)

-7 ( 210+195)

13770+ 8100-2835)

= 19035

FINAL ANSWER- 19035

#SPJ3

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