Math, asked by smriddhirawat56341, 3 months ago

All numbers divisible by both 14 and 10 are also divisible by which of the following?

Answers

Answered by Royalleajents
0

Answer:

14 is divisible by 7, because 14 ÷ 7 = 2 exactly ... These rules let you test if one number is divisible by another, without having to do too much ... 217 (2+1+7=10, and 10÷3 = 3 1/3) No.

Answered by charanyahb
0

Answer:

35

Step-by-step explanation:

A number is divisible by another number (a divisor) if its prime factorization contains the prime factorization of the divisor.

A number is divisible by another number (a divisor) if its prime factorization contains the prime factorization of the divisor.The prime factorization of 14 is 2 x 7.

A number is divisible by another number (a divisor) if its prime factorization contains the prime factorization of the divisor.The prime factorization of 14 is 2 x 7.The prime factorization of 10 is 2 × 5.

A number is divisible by another number (a divisor) if its prime factorization contains the prime factorization of the divisor.The prime factorization of 14 is 2 x 7.The prime factorization of 10 is 2 × 5.So, any number divisible by both must have 2 x 5 x 7 as part of its prime factorization.

A number is divisible by another number (a divisor) if its prime factorization contains the prime factorization of the divisor.The prime factorization of 14 is 2 x 7.The prime factorization of 10 is 2 × 5.So, any number divisible by both must have 2 x 5 x 7 as part of its prime factorization.All numbers which divide such a number will have a factorization which is part of 2 × 5 × 7.

The prime factorization of 35 is 5 x 7.

The prime factorization of 35 is 5 x 7.Since 5 x 7 is part of 2 x 5 x 7, all numbers which are divisible by 14 and 10 are also divisible by 35.

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