Question

ALL OF THOSE WHO DO NOT HAVE A PURPOSE IN LIFE AND LIKE TO SPAM.. MAY IGNORE THIS QUESTION SINCE IT IS NOT MADE FOR THEM​​....

ans is a) 6.28 rad/s
b)376.8 rad
pls show the working i couldn't solve this sum​

Answer 1

Question:

A ball attatched to the end of a horizontal cord is revolved in a circle of radius 2m at a constant speed 60rpm. Determine (a) the magnitude of angular speed after 2 seconds.(b) angular displacement after 1 minute. (1 revolution/second = 2π radians/second)

Answer:

$\bigstar{\bold{Angular\:speed\:=\:6.28\:rad/s}}$

$\bigstar{\bold{Angular\:displacement\:=\:376.8\:rad}}$

Explanation:

$\Large{\underline{\underline{\bf{Given:}}}}$

• Radius(r) = 2m
• Speed = 60rpm

$\Large{\underline{\underline{\bf{To\:Find:}}}}$

• (a) Angular speed (ω)
• (b) Angular displacement (θ)

$\Large{\underline{\underline{\bf{Solution:}}}}$

a) Angular speed:

→ Time taken = 2s

→ Distance travelled = Perimeter of circle= 2πr=2×3.14×2=12.56

→ Angular speed is given by the formula

   Angular speed = Distance travelled/Time taken

→ Substituting the datas, we get

    ω = 12.56/2 = 6.28 rad/s

   $\boxed{\bold{Angular\:speed\:(\omega)\:=\:6.28\:rad/s}}$

b) Angular displacement:

→ Time taken= 1min = 60s

→ The formula for displacement is given by

   Displacement = Speed× Time

→ Substituting the given datas, we get

  θ = 6.28×60 = 376.8 rad

  $\boxed{\bold{Angular\:displacement\:(\theta)\:=\:376.8\:rad}}$

Answer 2

Answer:

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