Physics, asked by bushrariyaz41, 1 day ago

All physics experts out there solve this one:

Q. A body travels equal distances by speed V1 and V2 . calculate the avg. speed?

Answers

Answered by battulamaneesh2
1

Answer:

Avg Speed = (2*V1*V2) / (V1+V2)

Explanation:

Avg Speed = (Total distance)/(Total time taken)

Since the distances are same, Let S be the distance

Total distance = S+S = 2*S

T1 = S/V1   (Time taken to cover distance S with speed V1)

T2 = S/V2 (Time taken to cover distance S with speed V2)

Total time = T1+T2

                 = (S/V1) + (S/V2)

                 = (S*(V1+V2)) / (V1*V2)

Avg Speed = (Total distance)/(Total time taken)

                   = (2*S) / [(S*(V1+V2)) / (V1*V2)]

                   = (2*V1*V2) / (V1+V2)

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