Math, asked by dandgesharan1999, 3 months ago

all polinomial formulae​

Answers

Answered by devika2271
3

Answer:

Polynomial Identities

(x + y)2= x2 + 2xy + y2

(x – y)2= x2 – 2xy + y2

x2– y2 = (x + y)(x – y)

(x + a)(x + b) = x2+ (a + b)x + ab

(x + y + z)2= x2 + y2 + c2 + 2xy + 2yz + 2zx

(x + y)3= x3 + y3 + 3xy (x + y)

(x – y)3= x3 – y3 – 3xy (x – y)

x3+ y3 = (x + y)(x2 – xy + y2)

x3– y3 = (x – y)(x2 + xy + y2)

x3+ y3 + z3 – 3xyz = (x + y + z)(x2 + y2 + z2 – xy – yz – zx)

ax2 + bx + c = 0 then x = \frac{( -b \pm \sqrt{(b2 – 4ac)} )}{2a}

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