Question

all Questions Answer ​

Answer 1

Question-1) Radhika sells a washing machine for Rs 8800 at a loss of 20% . what was the price at which she bought it ?

Solution-1)

Sp = ₹ 8800

loss% = 20%

To find = CP

$cp = \frac{(sp \times 100)}{100 - (\%l)} \\ cp = \frac{8800 \times 100}{80} \\ cp = \frac{8800 \times 10}{8} \\ cp = 1100 \times 10 \\ cp = rs \: 1100$

Ans: ₹ 11,000

Question-1)(or) Sunita takes a lone of ₹7000 at 3.5% per year as rate of simple interest. find the amount to be paid at the end of second .

Solution-1)

P = ₹ 7000

R = 3.5% p.a

T= 2 years

$si \: = \frac{p \times r \times t}{100} \\ si = \frac{7000 \times 3.5 \times 2}{100} \\ si = \frac{70 \times 35}{10} \\ = 7\times 70 \\ = 490 \\ amount = p + si \\ amount = 7000 + 490 \\ amount = 7490$

Ans1(or) ₹7490

(construction do yourself )

Question22

simplification :

$3 \frac{3}{7} \div \frac{8}{21} \times \frac{1}{21} = \\ \frac{24}{7} \times \frac{21}{8} \times \frac{1}{21} = \frac{3}{7}$

Question

0.089×0.76÷0.19

$\frac{0.06764}{0.19} = 0.356$

thanks