all sums on quadrilateral with solutions
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Sum of angles of a quadrilateral are discussed here.
We know, the sum of the angles of a triangle = 180°
Since there are two triangles,
therefore, the sum of two triangles is 180° + 180° = 360°
Note: The sum of the four angles is 360°.
1. In a quadrilateral ABCD, ∠A = 100°, ∠B = 105° and ∠C = 70°, find ∠D.
Solution:
Here the sum of the four angles
or, ∠A + ∠B + ∠C + ∠D = 360°
We know, ∠A = 100°, ∠B = 105° and ∠C = 70°
or, 100° + 105° + 70° + ∠D = 360°
or, 275° + ∠D = 360°
∠D = 360° - 275°
Therefore, ∠D = 85°
We know, the sum of the angles of a triangle = 180°
Since there are two triangles,
therefore, the sum of two triangles is 180° + 180° = 360°
Note: The sum of the four angles is 360°.
1. In a quadrilateral ABCD, ∠A = 100°, ∠B = 105° and ∠C = 70°, find ∠D.
Solution:
Here the sum of the four angles
or, ∠A + ∠B + ∠C + ∠D = 360°
We know, ∠A = 100°, ∠B = 105° and ∠C = 70°
or, 100° + 105° + 70° + ∠D = 360°
or, 275° + ∠D = 360°
∠D = 360° - 275°
Therefore, ∠D = 85°
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