Question

all the besties, answer the question.

x^2+xy-2xz-2yz

from factorisation

Answer 1

Given Equation is x^2 + xy - 2xz - 2yz

It can be written as follows:

⇒ x^2 - 2xz + xy - 2yz

⇒ x(x - 2z) + y(x - 2z)

⇒ (x + y)(x - 2z)

Therefore, factorization of x^2 + xy - 2xz - 2yz = (x + y)(x - 2z).

Hope this helps!

Answer 2

Solution :

x^{2} + xy - 2xz - 2yz

= ( x^{2} + xy ) - ( 2xz + 2yz )

Take x as common in ( x^{2} + xy ) and 2z as common in ( 2xz + 2yz )

= x × ( x + y ) - 2z × ( x + y )

= ( x + y ) ( x - 2z )