All the black face cards are removed from a pack of 52 cards.find the probability of getting (i) face card (ii) red card (iii) black card (iv) king
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Answered by
286
As there are 6 black face cards in a pack 52 cards , and those cards are removed so,
No. of cards in pack = 52-6 = 46.
i) P( face card) = No. of face cards / Total cards i.e. 6/46 = 3/23.
ii) P (red card) = No. of red cards / total cards
i.e. 26/46 = 13/23.
iii) P (black card) = No. of black card / Total cards i.e. 20/46 = 10/23.
iv) P (King) = No. of kings / total card
i.e. 2/46 = 1/23.
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No. of cards in pack = 52-6 = 46.
i) P( face card) = No. of face cards / Total cards i.e. 6/46 = 3/23.
ii) P (red card) = No. of red cards / total cards
i.e. 26/46 = 13/23.
iii) P (black card) = No. of black card / Total cards i.e. 20/46 = 10/23.
iv) P (King) = No. of kings / total card
i.e. 2/46 = 1/23.
Hope you will find it helpful.....
Mark it as brainliest.
Answered by
76
if all the black face cards are removed
i.. 6/46
= 3/23
ii.. 26/46
= 13/23
iii.. 20/46
= 10/23
iv. 2/46
= 1/23
i.. 6/46
= 3/23
ii.. 26/46
= 13/23
iii.. 20/46
= 10/23
iv. 2/46
= 1/23
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