All the edges of square pyramid are equal length. a, find lateral surface area. b, find slant height. c, find surface area. d, volume of square pyramid.
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Since all the edges of a square pyramid are of length 12 cm, lateral faces of the pyramid are equilateral triangles having each edge of 12 cm.
Thus, area of one lateral face =43×12×12=363sq.cm
(b) An edge =12 cm=a
Slant height =l=23×1=63cm
Surface area of pyramid
=a2+4×43a2
=122+43×122
=144×1443
=144(1+3)sq.cm
(c) Length of edge of pyramid, a=12 cm
New length of edge, a′=24 cm
New surface area of the pyramid
=(a′)2+4×43(a
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