Question

all the experts i am challenging u to solve this. the sum of the digits of a two digit number is 9 on reversing the digits,the new number is obtained is 45 more than the original number.find the number

Answer 1

Hey

Here is ur answer

Let the ones place be x and tens place be y

Then
Two digit number = 10*tens place +ones place

Two digit number = 10y+ x
According to question

x+y= 9➖ 1

Now after interchanging the digit
Then
New two digit number = 10x+y


According to question
10x+y = 10y+x + 45
9x -9y = 45

x-y= 5➖ 2
Solve the equation 1 and 2
We get
From equation 2
y= x-5 ➖ 3 Put it on equation 1 we get x+x-5=9 = 2x=14 x= 7 Put x=7 in equation 3 we get y= 7-5= 2 Therefore two digit number = 10y+ x = 10*2+7 = 27 Hope it helps you Expert are always available for helping the students ohk. Be a happy