Chemistry, asked by adnanstar1849, 7 months ago

All the following have nearly same size due to lanthanide contraction except (A) zr, Br (B) Mo, w (C) Nb, Ta (D) Y, La

Answers

Answered by nandika32
1

Answer:

Zirconium(Zr) and Bromine(Br)

Explanation:

Zirconium and Hafnium(Hf) have same size.

Answered by TheValkyrie
3

Answer:

\Large{\underline{\underline{\bf{Option\:A: \: Zr,\:Br}}}}

Explanation:

\dag This is because the size of the Zirconium atom is similar to that of Hafnium atom due to lanthanoid contraction and not to that of bromine atom.

\dag The atomic radius of Zr is 160 pm and that of Hf is 159 pm which is almost similar.

\Large{\underline{\underline{\bf{More\:information:}}}}

\dagLanthanoid contraction:

  • The filling of 4f before 5d orbitals which results in the decrease in the    atomic radii is called as lanthanoid contraction.

\dagFactor responsible for lanthanoid contraction:

  • The imperfect shielding of one electron by another in the same set of orbital is the reason for lanthanoid contraction. As a result the electrons experience effective nuclear charge and atomic radii gets reduced.

\dagConsequences of lanthanoid contraction:

  • The lanthanoid contraction results in the similar atomic radii of of the second and third d series.
  • They have very much similar physical and chemical properties which is much more than expected.
  • It results in general increase in density of the elements.

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