Question

All the formulas of trigonometry of class 10th​

Answer 1

$\Large\bf\red{\underline{\overline{\mid{\orange{Formulas \: of \: Trignometry \: Class \: 10:-}}\mid}}}$

• Property : sinA
• Mathematical Value : Perpendicular/hypotenuse

⠀⠀⠀⠀⠀⠀⠀ ⠀

• Property : cosA
• Mathematical Value : Base/hypotenuse

⠀⠀⠀⠀⠀⠀⠀ ⠀ ⠀

• Property : tanA
• Mathematical Value : perpendicular/base

⠀⠀⠀⠀⠀⠀⠀ ⠀ ⠀

• Property : cotA
• Mathematical Value : base/perpendicular

⠀⠀⠀⠀⠀⠀⠀ ⠀ ⠀

• Property : cos c A
• Mathematical Value : Hypotenuse/perpendicular

⠀⠀⠀⠀⠀⠀⠀ ⠀ ⠀

• Property : secA
• Mathematical Value : Hypotenuse Base

Rᴇᴄɪᴘʀᴏᴄᴀʟ Rᴇʟᴀᴛɪᴏɴ Bᴇᴛᴡᴇᴇɴ Tʀɪɢɴᴏᴍᴇᴛʀɪᴄ Rᴀᴛɪᴏs :

• Identity : tanA
• Relation : sinA/cosA

⠀⠀⠀⠀⠀⠀⠀ ⠀ ⠀

• Identity : cotA
• Relation : cosA/sinA

⠀⠀⠀⠀⠀⠀⠀ ⠀ ⠀

• Identity : cosecA
• Relation : 1/sinA

⠀⠀⠀⠀⠀⠀⠀ ⠀ ⠀

• Identity : secA
• Relation : 1/cosA

______________________________________

Answer 2

${ \red{ \bf{ Information \: related \: to \:Trigonometry:}}}$

${ \green{ \bf{ sin θ = Perpendicular/Hypotenuse }}}$

${ \green{ \bf{ cos θ = Base/Hypotenuse }}}$

${ \green{ \bf{tan θ = Perpendicular/Base }}}$

${ \green{ \bf{sec θ = Hypotenuse/Base }}}$

${ \green{ \bf{ cosec θ = Hypotenuse/Perpendicular }}}$

${ \green{ \bf{ cot θ = Base/Perpendicular }}}$

${ \red{ \bf{Their \: reciprocal \: Identities: }}}$

${ \green{ \bf{ cosec θ = 1/sin θ }}}$

${ \green{ \bf{ sec θ = 1/cos θ }}}$

${ \green{ \bf{ cot θ = 1/tan θ }}}$

${ \green{ \bf{sin θ = 1/cosec θ }}}$

${ \green{ \bf{ cos θ = 1/sec θ }}}$

${ \green{ \bf{ tan θ = 1/cot θ}}}$

${ \red{ \bf{ Their \: co-function \: Identities: }}}$

${ \green{ \bf{ sin (90°−x) = cos x }}}$

${ \green{ \bf{cos (90°−x) = sin x }}}$

${ \green{ \bf{ tan (90°−x) = cot x }}}$

${ \green{ \bf{ cot (90°−x) = tan x }}}$

${ \green{ \bf{ sec (90°−x) = cosec x }}}$

${ \green{ \bf{ cosec (90°−x) = sec x }}}$

${ \red{ \bf{ Their \: fundamental \: trigonometric \: identities: }}}$

${ \green{ \bf{ sin²θ + cos²θ = 1 }}}$

${ \green{ \bf{ sec²θ - tan²θ = 1 }}}$

${ \green{ \bf{ cosec²θ - cot²θ = 1 }}}$